Base | Representation |
---|---|
bin | 101110110000101111100… |
… | …111001100011110110101 |
3 | 102101012102202122012122212 |
4 | 232300233213030132311 |
5 | 410122103142410201 |
6 | 10500121550103205 |
7 | 451106620136642 |
oct | 56605747143665 |
9 | 12335382565585 |
10 | 3213434341301 |
11 | 102989aa03388 |
12 | 43a9507aab05 |
13 | 1a40441c7352 |
14 | b17612c6dc9 |
15 | 588c7313abb |
hex | 2ec2f9cc7b5 |
3213434341301 has 2 divisors, whose sum is σ = 3213434341302. Its totient is φ = 3213434341300.
The previous prime is 3213434341291. The next prime is 3213434341339. The reversal of 3213434341301 is 1031434343123.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2566051572100 + 647382769201 = 1601890^2 + 804601^2 .
It is a cyclic number.
It is not a de Polignac number, because 3213434341301 - 214 = 3213434324917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3213434341001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606717170650 + 1606717170651.
It is an arithmetic number, because the mean of its divisors is an integer number (1606717170651).
Almost surely, 23213434341301 is an apocalyptic number.
It is an amenable number.
3213434341301 is a deficient number, since it is larger than the sum of its proper divisors (1).
3213434341301 is an equidigital number, since it uses as much as digits as its factorization.
3213434341301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 3213434341301 its reverse (1031434343123), we get a palindrome (4244868684424).
The spelling of 3213434341301 in words is "three trillion, two hundred thirteen billion, four hundred thirty-four million, three hundred forty-one thousand, three hundred one".
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