Base | Representation |
---|---|
bin | 1110110000001110011001… |
… | …00100111100010111011111 |
3 | 11020212112212202202022221002 |
4 | 13120013030210330113133 |
5 | 13223022404434120244 |
6 | 153000131111100515 |
7 | 6555644501540144 |
oct | 730071444742737 |
9 | 136775782668832 |
10 | 32443320223199 |
11 | a37915351a096 |
12 | 377b89637173b |
13 | 1514513207402 |
14 | 80239d52c3cb |
15 | 3b3dd28d1a4e |
hex | 1d81cc93c5df |
32443320223199 has 2 divisors, whose sum is σ = 32443320223200. Its totient is φ = 32443320223198.
The previous prime is 32443320223121. The next prime is 32443320223201. The reversal of 32443320223199 is 99132202334423.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32443320223199 is a prime.
It is a super-2 number, since 2×324433202231992 (a number of 28 digits) contains 22 as substring.
Together with 32443320223201, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32443320123199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16221660111599 + 16221660111600.
It is an arithmetic number, because the mean of its divisors is an integer number (16221660111600).
Almost surely, 232443320223199 is an apocalyptic number.
32443320223199 is a deficient number, since it is larger than the sum of its proper divisors (1).
32443320223199 is an equidigital number, since it uses as much as digits as its factorization.
32443320223199 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1679616, while the sum is 47.
The spelling of 32443320223199 in words is "thirty-two trillion, four hundred forty-three billion, three hundred twenty million, two hundred twenty-three thousand, one hundred ninety-nine".
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