Base | Representation |
---|---|
bin | 101111001101101010010… |
… | …101101111111111011010 |
3 | 102111011120200210100212121 |
4 | 233031222111233333122 |
5 | 411124201001114340 |
6 | 10522255012331454 |
7 | 453256230216520 |
oct | 57155225577732 |
9 | 12434520710777 |
10 | 3244484394970 |
11 | 1040a83948265 |
12 | 444977313b8a |
13 | 1a6c51ca3280 |
14 | b3068d8c310 |
15 | 595e320994a |
hex | 2f36a56ffda |
3244484394970 has 64 divisors (see below), whose sum is σ = 7305613410816. Its totient is φ = 1009992602880.
The previous prime is 3244484394911. The next prime is 3244484395037. The reversal of 3244484394970 is 794934844423.
It is a super-2 number, since 2×32444843949702 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (61).
It is a junction number, because it is equal to n+sod(n) for n = 3244484394899 and 3244484394908.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29168814 + ... + 29279833.
It is an arithmetic number, because the mean of its divisors is an integer number (114150209544).
Almost surely, 23244484394970 is an apocalyptic number.
3244484394970 is an abundant number, since it is smaller than the sum of its proper divisors (4061129015846).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3244484394970 is a wasteful number, since it uses less digits than its factorization.
3244484394970 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58448735.
The product of its (nonzero) digits is 83607552, while the sum is 61.
The spelling of 3244484394970 in words is "three trillion, two hundred forty-four billion, four hundred eighty-four million, three hundred ninety-four thousand, nine hundred seventy".
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