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325112101310567 is a prime number
BaseRepresentation
bin100100111101100000000111…
…1010011111001000001100111
31120122010102011022220211111102
41021323000033103321001213
5320103114040413414232
63111242234255030315
7125323400642630354
oct11173001723710147
91518112138824442
10325112101310567
11946552a459792a
1230568aa0b0b39b
1310c53c2a40622c
145a3d71c72b62b
15278bda2734662
hex127b00f4f9067

325112101310567 has 2 divisors, whose sum is σ = 325112101310568. Its totient is φ = 325112101310566.

The previous prime is 325112101310449. The next prime is 325112101310569. The reversal of 325112101310567 is 765013101211523.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 325112101310567 - 210 = 325112101309543 is a prime.

It is a super-2 number, since 2×3251121013105672 (a number of 30 digits) contains 22 as substring.

Together with 325112101310569, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 325112101310567.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (325112101310569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162556050655283 + 162556050655284.

It is an arithmetic number, because the mean of its divisors is an integer number (162556050655284).

Almost surely, 2325112101310567 is an apocalyptic number.

325112101310567 is a deficient number, since it is larger than the sum of its proper divisors (1).

325112101310567 is an equidigital number, since it uses as much as digits as its factorization.

325112101310567 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37800, while the sum is 38.

The spelling of 325112101310567 in words is "three hundred twenty-five trillion, one hundred twelve billion, one hundred one million, three hundred ten thousand, five hundred sixty-seven".