Base | Representation |
---|---|
bin | 110000000010010011001… |
… | …100011101110101101001 |
3 | 102200120110200011012202020 |
4 | 300002103030131311221 |
5 | 413040424111331100 |
6 | 11004243244255053 |
7 | 460326652313301 |
oct | 60022314356551 |
9 | 12616420135666 |
10 | 3301004402025 |
11 | 1062a47a230a0 |
12 | 45390b841489 |
13 | 1ac38b77a525 |
14 | b5aab5b0601 |
15 | 5ad001a35a0 |
hex | 3009331dd69 |
3301004402025 has 48 divisors (see below), whose sum is σ = 6066147723840. Its totient is φ = 1570289094400.
The previous prime is 3301004401997. The next prime is 3301004402041. The reversal of 3301004402025 is 5202044001033.
It is not a de Polignac number, because 3301004402025 - 214 = 3301004385641 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 3301004401986 and 3301004402004.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 37703610 + ... + 37791059.
It is an arithmetic number, because the mean of its divisors is an integer number (126378077580).
Almost surely, 23301004402025 is an apocalyptic number.
It is an amenable number.
3301004402025 is a deficient number, since it is larger than the sum of its proper divisors (2765143321815).
3301004402025 is a wasteful number, since it uses less digits than its factorization.
3301004402025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75494746 (or 75494741 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 24.
Adding to 3301004402025 its reverse (5202044001033), we get a palindrome (8503048403058).
The spelling of 3301004402025 in words is "three trillion, three hundred one billion, four million, four hundred two thousand, twenty-five".
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