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3301255511341 is a prime number
BaseRepresentation
bin110000000010100010001…
…010010111110100101101
3102200121010011122212222021
4300002202022113310231
5413041432402330331
611004324214350141
7460336121565364
oct60024212276455
912617104585867
103301255511341
111063066744257
1245397b95b351
131ac3cb7bab18
14b5ad2a987db
155ad17256211
hex300a2297d2d

3301255511341 has 2 divisors, whose sum is σ = 3301255511342. Its totient is φ = 3301255511340.

The previous prime is 3301255511329. The next prime is 3301255511353. The reversal of 3301255511341 is 1431155521033.

It is a balanced prime because it is at equal distance from previous prime (3301255511329) and next prime (3301255511353).

It can be written as a sum of positive squares in only one way, i.e., 2119732164900 + 1181523346441 = 1455930^2 + 1086979^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3301255511341 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3301255511297 and 3301255511306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3301255511941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650627755670 + 1650627755671.

It is an arithmetic number, because the mean of its divisors is an integer number (1650627755671).

Almost surely, 23301255511341 is an apocalyptic number.

It is an amenable number.

3301255511341 is a deficient number, since it is larger than the sum of its proper divisors (1).

3301255511341 is an equidigital number, since it uses as much as digits as its factorization.

3301255511341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27000, while the sum is 34.

The spelling of 3301255511341 in words is "three trillion, three hundred one billion, two hundred fifty-five million, five hundred eleven thousand, three hundred forty-one".