Base | Representation |
---|---|
bin | 1111000011111100111000… |
… | …01100000000010011100010 |
3 | 11100021100101022211200101120 |
4 | 13201332130030000103202 |
5 | 13320124014440242010 |
6 | 154235343535113110 |
7 | 6655631030100156 |
oct | 741763414002342 |
9 | 140240338750346 |
10 | 33121113212130 |
11 | a60a648a40679 |
12 | 386b115972796 |
13 | 15633cc981ac8 |
14 | 8270db3a7066 |
15 | 3c68520b8e70 |
hex | 1e1f9c3004e2 |
33121113212130 has 32 divisors (see below), whose sum is σ = 79490982731904. Its totient is φ = 8832262298496.
The previous prime is 33121113212119. The next prime is 33121113212191. The reversal of 33121113212130 is 3121231112133.
It is a self number, because there is not a number n which added to its sum of digits gives 33121113212130.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6160734 + ... + 10207686.
It is an arithmetic number, because the mean of its divisors is an integer number (2484093210372).
Almost surely, 233121113212130 is an apocalyptic number.
33121113212130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
33121113212130 is an abundant number, since it is smaller than the sum of its proper divisors (46369869519774).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
33121113212130 is a wasteful number, since it uses less digits than its factorization.
33121113212130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4319770.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 33121113212130 its reverse (3121231112133), we get a palindrome (36242344324263).
The spelling of 33121113212130 in words is "thirty-three trillion, one hundred twenty-one billion, one hundred thirteen million, two hundred twelve thousand, one hundred thirty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •