Base | Representation |
---|---|
bin | 1001101000111011101… |
… | …10100001000001100100 |
3 | 1011122220211021120102102 |
4 | 10310131312201001210 |
5 | 20411311101441400 |
6 | 412053550431232 |
7 | 32633526462266 |
oct | 4643566410144 |
9 | 1148824246372 |
10 | 331213312100 |
11 | 118515309700 |
12 | 54236802518 |
13 | 25305699458 |
14 | 12060783b36 |
15 | 8937aa29d5 |
hex | 4d1dda1064 |
331213312100 has 108 divisors (see below), whose sum is σ = 790361486544. Its totient is φ = 120387960000.
The previous prime is 331213312081. The next prime is 331213312103. The reversal of 331213312100 is 1213312133.
It is a super-2 number, since 2×3312133121002 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (331213312103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 36428555 + ... + 36437645.
Almost surely, 2331213312100 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 331213312100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (395180743272).
331213312100 is an abundant number, since it is smaller than the sum of its proper divisors (459148174444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
331213312100 is a wasteful number, since it uses less digits than its factorization.
331213312100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12138 (or 12120 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 331213312100 its reverse (1213312133), we get a palindrome (332426624233).
It can be divided in two parts, 3312133 and 12100, that added together give a palindrome (3324233).
The spelling of 331213312100 in words is "three hundred thirty-one billion, two hundred thirteen million, three hundred twelve thousand, one hundred".
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