Base | Representation |
---|---|
bin | 110000001101100100111… |
… | …000001000000110000000 |
3 | 102201201201111011002121012 |
4 | 300031210320020012000 |
5 | 413240223212020112 |
6 | 11014004525020052 |
7 | 461236003133246 |
oct | 60154470100600 |
9 | 12651644132535 |
10 | 3313112220032 |
11 | 10680a0525a5a |
12 | 45612a6b4628 |
13 | 1b056b062194 |
14 | b64d9656796 |
15 | 5b2ad120022 |
hex | 30364e08180 |
3313112220032 has 16 divisors (see below), whose sum is σ = 6600340751100. Its totient is φ = 1656556109952.
The previous prime is 3313112220031. The next prime is 3313112220139. The reversal of 3313112220032 is 2300222113133.
It is a tau number, because it is divible by the number of its divisors (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3313112220031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12941844482 + ... + 12941844737.
Almost surely, 23313112220032 is an apocalyptic number.
3313112220032 is a gapful number since it is divisible by the number (32) formed by its first and last digit.
It is an amenable number.
3313112220032 is a deficient number, since it is larger than the sum of its proper divisors (3287228531068).
3313112220032 is an equidigital number, since it uses as much as digits as its factorization.
3313112220032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25883689233 (or 25883689221 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 3313112220032 its reverse (2300222113133), we get a palindrome (5613334333165).
The spelling of 3313112220032 in words is "three trillion, three hundred thirteen billion, one hundred twelve million, two hundred twenty thousand, thirty-two".
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