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33144040439189 is a prime number
BaseRepresentation
bin1111000100100111100101…
…10000011011110110010101
311100100112120011110111021022
413202103302300123312111
513321012443323023224
6154254054553130525
76660402135233561
oct742236260336625
9140315504414238
1033144040439189
11a619343845709
1238736540b9a45
131565614941254
148282743506a1
153c7244d0165e
hex1e24f2c1bd95

33144040439189 has 2 divisors, whose sum is σ = 33144040439190. Its totient is φ = 33144040439188.

The previous prime is 33144040439161. The next prime is 33144040439227. The reversal of 33144040439189 is 98193404044133.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28927724402500 + 4216316036689 = 5378450^2 + 2053367^2 .

It is an emirp because it is prime and its reverse (98193404044133) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33144040439189 - 220 = 33144039390613 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 33144040439189.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33144040439689) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16572020219594 + 16572020219595.

It is an arithmetic number, because the mean of its divisors is an integer number (16572020219595).

Almost surely, 233144040439189 is an apocalyptic number.

It is an amenable number.

33144040439189 is a deficient number, since it is larger than the sum of its proper divisors (1).

33144040439189 is an equidigital number, since it uses as much as digits as its factorization.

33144040439189 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4478976, while the sum is 53.

The spelling of 33144040439189 in words is "thirty-three trillion, one hundred forty-four billion, forty million, four hundred thirty-nine thousand, one hundred eighty-nine".