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3315399243311 is a prime number
BaseRepresentation
bin110000001111101101001…
…100011011011000101111
3102201221121212120220202002
4300033231030123120233
5413304414201241221
611015023503522515
7461346453406511
oct60175514333057
912657555526662
103315399243311
111069064493441
124566685b943b
131b0843b128ac
14b66752a7bb1
155b393ccb80b
hex303ed31b62f

3315399243311 has 2 divisors, whose sum is σ = 3315399243312. Its totient is φ = 3315399243310.

The previous prime is 3315399243293. The next prime is 3315399243313. The reversal of 3315399243311 is 1133429935133.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3315399243311 is a prime.

It is a super-3 number, since 3×33153992433113 (a number of 39 digits) contains 333 as substring.

It is a Sophie Germain prime.

Together with 3315399243313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3315399243313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657699621655 + 1657699621656.

It is an arithmetic number, because the mean of its divisors is an integer number (1657699621656).

Almost surely, 23315399243311 is an apocalyptic number.

3315399243311 is a deficient number, since it is larger than the sum of its proper divisors (1).

3315399243311 is an equidigital number, since it uses as much as digits as its factorization.

3315399243311 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 787320, while the sum is 47.

The spelling of 3315399243311 in words is "three trillion, three hundred fifteen billion, three hundred ninety-nine million, two hundred forty-three thousand, three hundred eleven".