33201441253 has 2 divisors, whose sum is σ = 33201441254. Its totient is φ = 33201441252.

The previous prime is 33201441197. The next prime is 33201441281. The reversal of 33201441253 is 35214410233.

It is a happy number.

It is an a-pointer prime, because the next prime (33201441281) can be obtained adding 33201441253 to its sum of digits (28).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23060548449 + 10140892804 = 151857^2 + 100702^2 .

It is an emirp because it is prime and its reverse (35214410233) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33201441253 - 2¹³ = 33201433061 is a prime.

It is a super-2 number, since 2×33201441253² (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33201441283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16600720626 + 16600720627.

It is an arithmetic number, because the mean of its divisors is an integer number (16600720627).

Almost surely, 2^33201441253 is an apocalyptic number.

It is an amenable number.

33201441253 is a deficient number, since it is larger than the sum of its proper divisors (1).

33201441253 is an equidigital number, since it uses as much as digits as its factorization.

33201441253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 33201441253 its reverse (35214410233), we get a palindrome (68415851486).

The spelling of 33201441253 in words is "thirty-three billion, two hundred one million, four hundred forty-one thousand, two hundred fifty-three".