Base | Representation |
---|---|
bin | 1111000110100101000011… |
… | …11100000001101100011110 |
3 | 11100120222102211212221112010 |
4 | 13203102201330001230132 |
5 | 13323113423411000110 |
6 | 154345035224052050 |
7 | 6665305360114644 |
oct | 743224174015436 |
9 | 140528384787463 |
10 | 33211404000030 |
11 | a644971813a43 |
12 | 3884714004026 |
13 | 156ba8bac7b19 |
14 | 82b624b5b194 |
15 | 3c8d88c35020 |
hex | 1e34a1f01b1e |
33211404000030 has 64 divisors (see below), whose sum is σ = 79769809946880. Its totient is φ = 8849437795584.
The previous prime is 33211404000007. The next prime is 33211404000043. The reversal of 33211404000030 is 3000040411233.
It is a super-2 number, since 2×332114040000302 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 33211403999970 and 33211404000006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 535144762 + ... + 535206818.
It is an arithmetic number, because the mean of its divisors is an integer number (1246403280420).
Almost surely, 233211404000030 is an apocalyptic number.
33211404000030 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
33211404000030 is an abundant number, since it is smaller than the sum of its proper divisors (46558405946850).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
33211404000030 is a wasteful number, since it uses less digits than its factorization.
33211404000030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75753.
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 33211404000030 its reverse (3000040411233), we get a palindrome (36211444411263).
The spelling of 33211404000030 in words is "thirty-three trillion, two hundred eleven billion, four hundred four million, thirty", and thus it is an aban number.
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