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335034040493 is a prime number
BaseRepresentation
bin1001110000000011001…
…01011100000010101101
31012000210002122200110102
410320001211130002231
520442122203243433
6413525034120445
733130312233155
oct4700145340255
91160702580412
10335034040493
1111a0a5a88479
1254b22280125
1325794110699
1412303d8d765
158aad2154e8
hex4e0195c0ad

335034040493 has 2 divisors, whose sum is σ = 335034040494. Its totient is φ = 335034040492.

The previous prime is 335034040487. The next prime is 335034040567. The reversal of 335034040493 is 394040430533.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 184554441604 + 150479598889 = 429598^2 + 387917^2 .

It is an emirp because it is prime and its reverse (394040430533) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 335034040493 - 210 = 335034039469 is a prime.

It is a super-2 number, since 2×3350340404932 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (335034040403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167517020246 + 167517020247.

It is an arithmetic number, because the mean of its divisors is an integer number (167517020247).

Almost surely, 2335034040493 is an apocalyptic number.

It is an amenable number.

335034040493 is a deficient number, since it is larger than the sum of its proper divisors (1).

335034040493 is an equidigital number, since it uses as much as digits as its factorization.

335034040493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 233280, while the sum is 38.

The spelling of 335034040493 in words is "three hundred thirty-five billion, thirty-four million, forty thousand, four hundred ninety-three".