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3354113431400 = 235216770567157
BaseRepresentation
bin110000110011110000101…
…111010101011101101000
3102212122112221011102220012
4300303300233111131220
5414423211014301100
611044505231151052
7464220025521524
oct60636057253550
912778487142805
103354113431400
111083520654a06
12462071975488
131b43a36870b4
14b84a8ba8d84
155c3ac977135
hex30cf0bd5768

3354113431400 has 24 divisors (see below), whose sum is σ = 7798313728470. Its totient is φ = 1341645372480.

The previous prime is 3354113431349. The next prime is 3354113431421. The reversal of 3354113431400 is 41343114533.

It can be written as a sum of positive squares in 3 ways, for example, as 1985489537476 + 1368623893924 = 1409074^2 + 1169882^2 .

It is a super-2 number, since 2×33541134314002 (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 8385283379 + ... + 8385283778.

Almost surely, 23354113431400 is an apocalyptic number.

It is an amenable number.

3354113431400 is an abundant number, since it is smaller than the sum of its proper divisors (4444200297070).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3354113431400 is a wasteful number, since it uses less digits than its factorization.

3354113431400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16770567173 (or 16770567164 counting only the distinct ones).

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 3354113431400 its reverse (41343114533), we get a palindrome (3395456545933).

The spelling of 3354113431400 in words is "three trillion, three hundred fifty-four billion, one hundred thirteen million, four hundred thirty-one thousand, four hundred".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 200 16770567157 33541134314 67082268628 83852835785 134164537256 167705671570 335411343140 419264178925 670822686280 838528357850 1677056715700 3354113431400