Base | Representation |
---|---|
bin | 110000110011110000101… |
… | …111010101011101101000 |
3 | 102212122112221011102220012 |
4 | 300303300233111131220 |
5 | 414423211014301100 |
6 | 11044505231151052 |
7 | 464220025521524 |
oct | 60636057253550 |
9 | 12778487142805 |
10 | 3354113431400 |
11 | 1083520654a06 |
12 | 462071975488 |
13 | 1b43a36870b4 |
14 | b84a8ba8d84 |
15 | 5c3ac977135 |
hex | 30cf0bd5768 |
3354113431400 has 24 divisors (see below), whose sum is σ = 7798313728470. Its totient is φ = 1341645372480.
The previous prime is 3354113431349. The next prime is 3354113431421. The reversal of 3354113431400 is 41343114533.
It can be written as a sum of positive squares in 3 ways, for example, as 1985489537476 + 1368623893924 = 1409074^2 + 1169882^2 .
It is a super-2 number, since 2×33541134314002 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 8385283379 + ... + 8385283778.
Almost surely, 23354113431400 is an apocalyptic number.
It is an amenable number.
3354113431400 is an abundant number, since it is smaller than the sum of its proper divisors (4444200297070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3354113431400 is a wasteful number, since it uses less digits than its factorization.
3354113431400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16770567173 (or 16770567164 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 3354113431400 its reverse (41343114533), we get a palindrome (3395456545933).
The spelling of 3354113431400 in words is "three trillion, three hundred fifty-four billion, one hundred thirteen million, four hundred thirty-one thousand, four hundred".
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