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34055343341150 = 2521525994463377
BaseRepresentation
bin1111011111001001000001…
…01001000111111001011110
311110120122210102122111010012
413233210200221013321132
513430430320343404100
6200232450405043222
710113263104134215
oct757444051077136
9143518712574105
1034055343341150
11a93a876549a9a
1239a01a16b6512
131600535cca611
1485a40493407c
153e0cce7a1135
hex1ef920a47e5e

34055343341150 has 24 divisors (see below), whose sum is σ = 63343367900400. Its totient is φ = 13622045016960.

The previous prime is 34055343341119. The next prime is 34055343341153. The reversal of 34055343341150 is 5114334355043.

It is a junction number, because it is equal to n+sod(n) for n = 34055343341098 and 34055343341107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34055343341153) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5398262 + ... + 9861638.

It is an arithmetic number, because the mean of its divisors is an integer number (2639306995850).

Almost surely, 234055343341150 is an apocalyptic number.

34055343341150 is a deficient number, since it is larger than the sum of its proper divisors (29288024559250).

34055343341150 is a wasteful number, since it uses less digits than its factorization.

34055343341150 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4615988 (or 4615983 counting only the distinct ones).

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 34055343341150 its reverse (5114334355043), we get a palindrome (39169677696193).

The spelling of 34055343341150 in words is "thirty-four trillion, fifty-five billion, three hundred forty-three million, three hundred forty-one thousand, one hundred fifty".

Divisors: 1 2 5 10 25 50 152599 305198 762995 1525990 3814975 4463377 7629950 8926754 22316885 44633770 111584425 223168850 681106866823 1362213733646 3405534334115 6811068668230 17027671670575 34055343341150