Base | Representation |
---|---|
bin | 1111011111001001000001… |
… | …01001000111111001011110 |
3 | 11110120122210102122111010012 |
4 | 13233210200221013321132 |
5 | 13430430320343404100 |
6 | 200232450405043222 |
7 | 10113263104134215 |
oct | 757444051077136 |
9 | 143518712574105 |
10 | 34055343341150 |
11 | a93a876549a9a |
12 | 39a01a16b6512 |
13 | 1600535cca611 |
14 | 85a40493407c |
15 | 3e0cce7a1135 |
hex | 1ef920a47e5e |
34055343341150 has 24 divisors (see below), whose sum is σ = 63343367900400. Its totient is φ = 13622045016960.
The previous prime is 34055343341119. The next prime is 34055343341153. The reversal of 34055343341150 is 5114334355043.
It is a junction number, because it is equal to n+sod(n) for n = 34055343341098 and 34055343341107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34055343341153) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5398262 + ... + 9861638.
It is an arithmetic number, because the mean of its divisors is an integer number (2639306995850).
Almost surely, 234055343341150 is an apocalyptic number.
34055343341150 is a deficient number, since it is larger than the sum of its proper divisors (29288024559250).
34055343341150 is a wasteful number, since it uses less digits than its factorization.
34055343341150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4615988 (or 4615983 counting only the distinct ones).
The product of its (nonzero) digits is 648000, while the sum is 41.
Adding to 34055343341150 its reverse (5114334355043), we get a palindrome (39169677696193).
The spelling of 34055343341150 in words is "thirty-four trillion, fifty-five billion, three hundred forty-three million, three hundred forty-one thousand, one hundred fifty".
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