34104143311151 has 2 divisors, whose sum is σ = 34104143311152. Its totient is φ = 34104143311150.

The previous prime is 34104143311031. The next prime is 34104143311153. The reversal of 34104143311151 is 15111334140143.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 34104143311151 - 2²² = 34104139116847 is a prime.

It is a Sophie Germain prime.

Together with 34104143311153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34104143311153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17052071655575 + 17052071655576.

It is an arithmetic number, because the mean of its divisors is an integer number (17052071655576).

Almost surely, 2^{34104143311151} is an apocalyptic number.

34104143311151 is a deficient number, since it is larger than the sum of its proper divisors (1).

34104143311151 is an equidigital number, since it uses as much as digits as its factorization.

34104143311151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 32.

Adding to 34104143311151 its reverse (15111334140143), we get a palindrome (49215477451294).

The spelling of 34104143311151 in words is "thirty-four trillion, one hundred four billion, one hundred forty-three million, three hundred eleven thousand, one hundred fifty-one".