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341120981138453 is a prime number
BaseRepresentation
bin100110110001111110110101…
…0111001111111110000010101
31122201210211212200122122002022
41031203331222321333300111
5324202411232132412303
63205300452040422525
7131565114625151165
oct11543755271776025
91581724780578068
10341120981138453
119976766093542a
1232313646477a45
13118457554b7469
1460344b4adc5a5
152968515ea0438
hex1363f6ae7fc15

341120981138453 has 2 divisors, whose sum is σ = 341120981138454. Its totient is φ = 341120981138452.

The previous prime is 341120981138393. The next prime is 341120981138477. The reversal of 341120981138453 is 354831189021143.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 252942082647409 + 88178898491044 = 15904153^2 + 9390362^2 .

It is a cyclic number.

It is not a de Polignac number, because 341120981138453 - 246 = 270752236960789 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 341120981138395 and 341120981138404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (341120981138753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170560490569226 + 170560490569227.

It is an arithmetic number, because the mean of its divisors is an integer number (170560490569227).

Almost surely, 2341120981138453 is an apocalyptic number.

It is an amenable number.

341120981138453 is a deficient number, since it is larger than the sum of its proper divisors (1).

341120981138453 is an equidigital number, since it uses as much as digits as its factorization.

341120981138453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2488320, while the sum is 53.

The spelling of 341120981138453 in words is "three hundred forty-one trillion, one hundred twenty billion, nine hundred eighty-one million, one hundred thirty-eight thousand, four hundred fifty-three".