Base | Representation |
---|---|
bin | 110001101001101100010… |
… | …000001000111110001000 |
3 | 110002012000112222020122110 |
4 | 301221230100020332020 |
5 | 421400304133002100 |
6 | 11131243242222320 |
7 | 501340020125634 |
oct | 61515420107610 |
9 | 13065015866573 |
10 | 3412020203400 |
11 | 10a60364a9876 |
12 | 4713327b49a0 |
13 | 1b99a1557923 |
14 | bb1dd655dc4 |
15 | 5db4b54e250 |
hex | 31a6c408f88 |
3412020203400 has 48 divisors (see below), whose sum is σ = 10577262632400. Its totient is φ = 909872054080.
The previous prime is 3412020203377. The next prime is 3412020203419. The reversal of 3412020203400 is 43020202143.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2843349570 + ... + 2843350769.
It is an arithmetic number, because the mean of its divisors is an integer number (220359638175).
Almost surely, 23412020203400 is an apocalyptic number.
3412020203400 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
3412020203400 is an abundant number, since it is smaller than the sum of its proper divisors (7165242429000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3412020203400 is a wasteful number, since it uses less digits than its factorization.
3412020203400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5686700358 (or 5686700349 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 21.
Adding to 3412020203400 its reverse (43020202143), we get a palindrome (3455040405543).
The spelling of 3412020203400 in words is "three trillion, four hundred twelve billion, twenty million, two hundred three thousand, four hundred".
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