Base | Representation |
---|---|
bin | 110001101010111111001… |
… | …101111110000000100111 |
3 | 110002022121120011010000021 |
4 | 301222333031332000213 |
5 | 421411132002040033 |
6 | 11132033324300011 |
7 | 501416351331202 |
oct | 61527715760047 |
9 | 13068546133007 |
10 | 3413412143143 |
11 | 10a66901927a2 |
12 | 4716609a1607 |
13 | 1b9b63a43702 |
14 | bb2d246a939 |
15 | 5dbcd850b2d |
hex | 31abf37e027 |
3413412143143 has 2 divisors, whose sum is σ = 3413412143144. Its totient is φ = 3413412143142.
The previous prime is 3413412143059. The next prime is 3413412143177.
3413412143143 is nontrivially palindromic in base 10.
It is an a-pointer prime, because the next prime (3413412143177) can be obtained adding 3413412143143 to its sum of digits (34).
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3413412143143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3413412143099 and 3413412143108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3413412143443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706706071571 + 1706706071572.
It is an arithmetic number, because the mean of its divisors is an integer number (1706706071572).
Almost surely, 23413412143143 is an apocalyptic number.
3413412143143 is a deficient number, since it is larger than the sum of its proper divisors (1).
3413412143143 is an equidigital number, since it uses as much as digits as its factorization.
3413412143143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 41472, while the sum is 34.
The spelling of 3413412143143 in words is "three trillion, four hundred thirteen billion, four hundred twelve million, one hundred forty-three thousand, one hundred forty-three".
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