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3422015061433 is a prime number
BaseRepresentation
bin110001110010111111111…
…111011111110110111001
3110010010211010001122022121
4301302333333133312321
5422031241323431213
611140015122521241
7502142503043503
oct61627777376671
913103733048277
103422015061433
1110aa2a5321621
12473261b06221
131ba9051647c7
14bb8aac3ad73
155e033c4388d
hex31cbffdfdb9

3422015061433 has 2 divisors, whose sum is σ = 3422015061434. Its totient is φ = 3422015061432.

The previous prime is 3422015061431. The next prime is 3422015061463. The reversal of 3422015061433 is 3341605102243.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2412156884544 + 1009858176889 = 1553112^2 + 1004917^2 .

It is a cyclic number.

It is not a de Polignac number, because 3422015061433 - 21 = 3422015061431 is a prime.

Together with 3422015061431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (3422015061431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1711007530716 + 1711007530717.

It is an arithmetic number, because the mean of its divisors is an integer number (1711007530717).

Almost surely, 23422015061433 is an apocalyptic number.

It is an amenable number.

3422015061433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3422015061433 is an equidigital number, since it uses as much as digits as its factorization.

3422015061433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 34.

The spelling of 3422015061433 in words is "three trillion, four hundred twenty-two billion, fifteen million, sixty-one thousand, four hundred thirty-three".