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342530495117 is a prime number
BaseRepresentation
bin1001111110000000110…
…10001001001010001101
31012202010112120000221222
410333000122021022031
521103000301320432
6421204545133125
733514140112046
oct4770032111215
91182115500858
10342530495117
111222a2597818
125647492a1a5
13263ba229a55
141281581b8cd
158d9b3e7112
hex4fc068928d

342530495117 has 2 divisors, whose sum is σ = 342530495118. Its totient is φ = 342530495116.

The previous prime is 342530495063. The next prime is 342530495119. The reversal of 342530495117 is 711594035243.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 219950682121 + 122579812996 = 468989^2 + 350114^2 .

It is a cyclic number.

It is not a de Polignac number, because 342530495117 - 234 = 325350625933 is a prime.

Together with 342530495119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (342530495119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171265247558 + 171265247559.

It is an arithmetic number, because the mean of its divisors is an integer number (171265247559).

Almost surely, 2342530495117 is an apocalyptic number.

It is an amenable number.

342530495117 is a deficient number, since it is larger than the sum of its proper divisors (1).

342530495117 is an equidigital number, since it uses as much as digits as its factorization.

342530495117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 453600, while the sum is 44.

The spelling of 342530495117 in words is "three hundred forty-two billion, five hundred thirty million, four hundred ninety-five thousand, one hundred seventeen".