34331131224130 has 64 divisors (see below), whose sum is σ = 70620038334720. Its totient is φ = 11919466665216.

The previous prime is 34331131224121. The next prime is 34331131224149. The reversal of 34331131224130 is 3142213113343.

It is a super-2 number, since 2×34331131224130² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34331131224092 and 34331131224101.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 97128537 + ... + 97481356.

It is an arithmetic number, because the mean of its divisors is an integer number (1103438098980).

Almost surely, 2^{34331131224130} is an apocalyptic number.

34331131224130 is an abundant number, since it is smaller than the sum of its proper divisors (36288907110590).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

34331131224130 is a wasteful number, since it uses less digits than its factorization.

34331131224130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 194609995.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 34331131224130 its reverse (3142213113343), we get a palindrome (37473344337473).

The spelling of 34331131224130 in words is "thirty-four trillion, three hundred thirty-one billion, one hundred thirty-one million, two hundred twenty-four thousand, one hundred thirty".