34422303210431 has 2 divisors, whose sum is σ = 34422303210432. Its totient is φ = 34422303210430.

The previous prime is 34422303210413. The next prime is 34422303210433. The reversal of 34422303210431 is 13401230322443.

Together with previous prime (34422303210413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (13401230322443) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-34422303210431 is a prime.

It is a super-4 number, since 4×34422303210431⁴ (a number of 55 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 34422303210433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34422303210433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17211151605215 + 17211151605216.

It is an arithmetic number, because the mean of its divisors is an integer number (17211151605216).

Almost surely, 2^{34422303210431} is an apocalyptic number.

34422303210431 is a deficient number, since it is larger than the sum of its proper divisors (1).

34422303210431 is an equidigital number, since it uses as much as digits as its factorization.

34422303210431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 34422303210431 its reverse (13401230322443), we get a palindrome (47823533532874).

The spelling of 34422303210431 in words is "thirty-four trillion, four hundred twenty-two billion, three hundred three million, two hundred ten thousand, four hundred thirty-one".