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34431326471 is a prime number
BaseRepresentation
bin100000000100010001…
…000101100100000111
310021212120121121111202
4200010101011210013
51031003404421341
623452330453115
72326145306003
oct400421054407
9107776547452
1034431326471
111366964a213
12680ab9419b
133329475a79
141948b99703
15d67b9e79b
hex804445907

34431326471 has 2 divisors, whose sum is σ = 34431326472. Its totient is φ = 34431326470.

The previous prime is 34431326437. The next prime is 34431326473. The reversal of 34431326471 is 17462313443.

It is a strong prime.

It is an emirp because it is prime and its reverse (17462313443) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34431326471 - 214 = 34431310087 is a prime.

It is a super-3 number, since 3×344313264713 (a number of 33 digits) contains 333 as substring.

Together with 34431326473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34431326473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17215663235 + 17215663236.

It is an arithmetic number, because the mean of its divisors is an integer number (17215663236).

Almost surely, 234431326471 is an apocalyptic number.

34431326471 is a deficient number, since it is larger than the sum of its proper divisors (1).

34431326471 is an equidigital number, since it uses as much as digits as its factorization.

34431326471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 145152, while the sum is 38.

The spelling of 34431326471 in words is "thirty-four billion, four hundred thirty-one million, three hundred twenty-six thousand, four hundred seventy-one".