Base | Representation |
---|---|
bin | 110010001101000100101… |
… | …010011011010101011111 |
3 | 110012211002011211000022222 |
4 | 302031010222123111133 |
5 | 423011110220231031 |
6 | 11200525114455555 |
7 | 504153324122306 |
oct | 62150452332537 |
9 | 13184064730288 |
10 | 3450010711391 |
11 | 1110161117812 |
12 | 4787757345bb |
13 | 1c04471bb55a |
14 | bcda4db743d |
15 | 5eb218eae7b |
hex | 32344a9b55f |
3450010711391 has 2 divisors, whose sum is σ = 3450010711392. Its totient is φ = 3450010711390.
The previous prime is 3450010711361. The next prime is 3450010711393. The reversal of 3450010711391 is 1931170100543.
It is a happy number.
3450010711391 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (1931170100543) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3450010711391 - 214 = 3450010695007 is a prime.
Together with 3450010711393, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3450010711393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1725005355695 + 1725005355696.
It is an arithmetic number, because the mean of its divisors is an integer number (1725005355696).
Almost surely, 23450010711391 is an apocalyptic number.
3450010711391 is a deficient number, since it is larger than the sum of its proper divisors (1).
3450010711391 is an equidigital number, since it uses as much as digits as its factorization.
3450010711391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 35.
The spelling of 3450010711391 in words is "three trillion, four hundred fifty billion, ten million, seven hundred eleven thousand, three hundred ninety-one".
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