Base | Representation |
---|---|
bin | 100000001010110011… |
… | …110101100001100111 |
3 | 10022011020011122021002 |
4 | 200022303311201213 |
5 | 1031220010132421 |
6 | 23511251343515 |
7 | 2331650332601 |
oct | 401263654147 |
9 | 108136148232 |
10 | 34541099111 |
11 | 13715606002 |
12 | 683b8b1b9b |
13 | 334612b7ac |
14 | 19595b2171 |
15 | d72634b0b |
hex | 80acf5867 |
34541099111 has 2 divisors, whose sum is σ = 34541099112. Its totient is φ = 34541099110.
The previous prime is 34541099081. The next prime is 34541099113. The reversal of 34541099111 is 11199014543.
It is a strong prime.
It is an emirp because it is prime and its reverse (11199014543) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34541099111 is a prime.
Together with 34541099113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34541099113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17270549555 + 17270549556.
It is an arithmetic number, because the mean of its divisors is an integer number (17270549556).
Almost surely, 234541099111 is an apocalyptic number.
34541099111 is a deficient number, since it is larger than the sum of its proper divisors (1).
34541099111 is an equidigital number, since it uses as much as digits as its factorization.
34541099111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 38.
The spelling of 34541099111 in words is "thirty-four billion, five hundred forty-one million, ninety-nine thousand, one hundred eleven".
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