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34541252113111 is a prime number
BaseRepresentation
bin1111101101010010000110…
…00011111111001011010111
311112022010000020201122102221
413312221003003333023113
514011410441020104421
6201244010540243211
710163344266426232
oct766510303771327
9145263006648387
1034541252113111
1110007954369287
123a5a3ab540507
1316372c2977623
14875b3c4d4419
153ed76d280841
hex1f6a430ff2d7

34541252113111 has 2 divisors, whose sum is σ = 34541252113112. Its totient is φ = 34541252113110.

The previous prime is 34541252113097. The next prime is 34541252113157. The reversal of 34541252113111 is 11131125214543.

It is a weak prime.

It is an emirp because it is prime and its reverse (11131125214543) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34541252113111 - 233 = 34532662178519 is a prime.

It is a super-3 number, since 3×345412521131113 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34541252110111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17270626056555 + 17270626056556.

It is an arithmetic number, because the mean of its divisors is an integer number (17270626056556).

Almost surely, 234541252113111 is an apocalyptic number.

34541252113111 is a deficient number, since it is larger than the sum of its proper divisors (1).

34541252113111 is an equidigital number, since it uses as much as digits as its factorization.

34541252113111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 34.

Adding to 34541252113111 its reverse (11131125214543), we get a palindrome (45672377327654).

The spelling of 34541252113111 in words is "thirty-four trillion, five hundred forty-one billion, two hundred fifty-two million, one hundred thirteen thousand, one hundred eleven".