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3531225432101 is a prime number
BaseRepresentation
bin110011011000101101011…
…100000000000000100101
3110111120201011122021212212
4303120231130000000211
5430323422202311401
611302120024053205
7513060025632563
oct63305534000045
913446634567785
103531225432101
111141647774504
12490460304205
131c7cbaba0003
14c2cab1d4a33
1561cc6861dbb
hex3362d700025

3531225432101 has 2 divisors, whose sum is σ = 3531225432102. Its totient is φ = 3531225432100.

The previous prime is 3531225432089. The next prime is 3531225432103. The reversal of 3531225432101 is 1012345221353.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3131802696100 + 399422736001 = 1769690^2 + 631999^2 .

It is a cyclic number.

It is not a de Polignac number, because 3531225432101 - 210 = 3531225431077 is a prime.

It is a super-2 number, since 2×35312254321012 (a number of 26 digits) contains 22 as substring.

Together with 3531225432103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3531225432103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1765612716050 + 1765612716051.

It is an arithmetic number, because the mean of its divisors is an integer number (1765612716051).

Almost surely, 23531225432101 is an apocalyptic number.

It is an amenable number.

3531225432101 is a deficient number, since it is larger than the sum of its proper divisors (1).

3531225432101 is an equidigital number, since it uses as much as digits as its factorization.

3531225432101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 32.

The spelling of 3531225432101 in words is "three trillion, five hundred thirty-one billion, two hundred twenty-five million, four hundred thirty-two thousand, one hundred one".