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3976381117133 is a prime number
BaseRepresentation
bin111001110111010010110…
…010001011001011001101
3112002010201211121010122122
4321313102302023023031
51010122112031222013
612242420235222325
7560166300550235
oct71672262131315
915063654533578
103976381117133
1112a3412527367
12542795ba79a5
1322ac8175bbb9
14da65a590cc5
156d67c69ca08
hex39dd2c8b2cd

3976381117133 has 2 divisors, whose sum is σ = 3976381117134. Its totient is φ = 3976381117132.

The previous prime is 3976381117097. The next prime is 3976381117153. The reversal of 3976381117133 is 3317111836793.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2218139592964 + 1758241524169 = 1489342^2 + 1325987^2 .

It is a cyclic number.

It is not a de Polignac number, because 3976381117133 - 26 = 3976381117069 is a prime.

It is a super-2 number, since 2×39763811171332 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3976381117153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1988190558566 + 1988190558567.

It is an arithmetic number, because the mean of its divisors is an integer number (1988190558567).

Almost surely, 23976381117133 is an apocalyptic number.

It is an amenable number.

3976381117133 is a deficient number, since it is larger than the sum of its proper divisors (1).

3976381117133 is an equidigital number, since it uses as much as digits as its factorization.

3976381117133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1714608, while the sum is 53.

The spelling of 3976381117133 in words is "three trillion, nine hundred seventy-six billion, three hundred eighty-one million, one hundred seventeen thousand, one hundred thirty-three".