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400145050051 is a prime number
BaseRepresentation
bin1011101001010101000…
…00001110100111000011
31102020211210111200020221
411310222200032213003
523023444113100201
6503454001043511
740623652543315
oct5645240164703
91366753450227
10400145050051
111447784a367a
1265673926597
132b96c6c6186
141551d55d7b5
15a61e4eb4a1
hex5d2a80e9c3

400145050051 has 2 divisors, whose sum is σ = 400145050052. Its totient is φ = 400145050050.

The previous prime is 400145050049. The next prime is 400145050103. The reversal of 400145050051 is 150050541004.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 400145050051 - 21 = 400145050049 is a prime.

It is a super-2 number, since 2×4001450500512 (a number of 24 digits) contains 22 as substring.

Together with 400145050049, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 400145049998 and 400145050025.

It is not a weakly prime, because it can be changed into another prime (400145050001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200072525025 + 200072525026.

It is an arithmetic number, because the mean of its divisors is an integer number (200072525026).

Almost surely, 2400145050051 is an apocalyptic number.

400145050051 is a deficient number, since it is larger than the sum of its proper divisors (1).

400145050051 is an equidigital number, since it uses as much as digits as its factorization.

400145050051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2000, while the sum is 25.

Adding to 400145050051 its reverse (150050541004), we get a palindrome (550195591055).

The spelling of 400145050051 in words is "four hundred billion, one hundred forty-five million, fifty thousand, fifty-one".