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4010355472133 is a prime number
BaseRepresentation
bin111010010110111011110…
…100000011011100000101
3112012101102120100012011002
4322112323310003130011
51011201202000102013
612310155403423045
7562511230033013
oct72267364033405
915171376305132
104010355472133
1113068671290aa
12549297b24a85
13231237336a3a
14dc1607958b3
156e4ba183358
hex3a5bbd03705

4010355472133 has 2 divisors, whose sum is σ = 4010355472134. Its totient is φ = 4010355472132.

The previous prime is 4010355472063. The next prime is 4010355472171. The reversal of 4010355472133 is 3312745530104.

It is an a-pointer prime, because the next prime (4010355472171) can be obtained adding 4010355472133 to its sum of digits (38).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2892985970884 + 1117369501249 = 1700878^2 + 1057057^2 .

It is a cyclic number.

It is not a de Polignac number, because 4010355472133 - 218 = 4010355209989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4010355472433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005177736066 + 2005177736067.

It is an arithmetic number, because the mean of its divisors is an integer number (2005177736067).

Almost surely, 24010355472133 is an apocalyptic number.

It is an amenable number.

4010355472133 is a deficient number, since it is larger than the sum of its proper divisors (1).

4010355472133 is an equidigital number, since it uses as much as digits as its factorization.

4010355472133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 38.

The spelling of 4010355472133 in words is "four trillion, ten billion, three hundred fifty-five million, four hundred seventy-two thousand, one hundred thirty-three".