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4012578255071 is a prime number
BaseRepresentation
bin111010011001000000010…
…011010011000011011111
3112012121011110220021010002
4322121000103103003133
51011220230013130241
612311204125404515
7562620300261521
oct72310023230337
915177143807102
104012578255071
1113077a78a98a1
125497b840973b
132314cc9b4409
14dc2d1a83a11
156e59a3a089b
hex3a6404d30df

4012578255071 has 2 divisors, whose sum is σ = 4012578255072. Its totient is φ = 4012578255070.

The previous prime is 4012578255043. The next prime is 4012578255107. The reversal of 4012578255071 is 1705528752104.

It is a happy number.

Together with next prime (4012578255107) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4012578255071 is a prime.

It is a super-2 number, since 2×40125782550712 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4012578255041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006289127535 + 2006289127536.

It is an arithmetic number, because the mean of its divisors is an integer number (2006289127536).

Almost surely, 24012578255071 is an apocalyptic number.

4012578255071 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012578255071 is an equidigital number, since it uses as much as digits as its factorization.

4012578255071 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 784000, while the sum is 47.

The spelling of 4012578255071 in words is "four trillion, twelve billion, five hundred seventy-eight million, two hundred fifty-five thousand, seventy-one".