40132312335 has 96 divisors (see below), whose sum is σ = 80902748160. Its totient is φ = 18254674944.

The previous prime is 40132312313. The next prime is 40132312349. The reversal of 40132312335 is 53321323104.

40132312335 is a `hidden beast` number, since 4 + 0 + 1 + 323 + 1 + 2 + 335 = 666.

It is not a de Polignac number, because 40132312335 - 2⁵ = 40132312303 is a prime.

It is a super-2 number, since 2×40132312335² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40132312299 and 40132312308.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 274282 + ... + 394328.

It is an arithmetic number, because the mean of its divisors is an integer number (842736960).

Almost surely, 2^40132312335 is an apocalyptic number.

40132312335 is a gapful number since it is divisible by the number (45) formed by its first and last digit.

40132312335 is an abundant number, since it is smaller than the sum of its proper divisors (40770435825).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

40132312335 is a wasteful number, since it uses less digits than its factorization.

40132312335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120117 (or 120114 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 27.

Adding to 40132312335 its reverse (53321323104), we get a palindrome (93453635439).

The spelling of 40132312335 in words is "forty billion, one hundred thirty-two million, three hundred twelve thousand, three hundred thirty-five".