40132631126351 has 2 divisors, whose sum is σ = 40132631126352. Its totient is φ = 40132631126350.

The previous prime is 40132631126311. The next prime is 40132631126353. The reversal of 40132631126351 is 15362113623104.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-40132631126351 is a prime.

It is a super-2 number, since 2×40132631126351² (a number of 28 digits) contains 22 as substring.

Together with 40132631126353, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40132631126353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066315563175 + 20066315563176.

It is an arithmetic number, because the mean of its divisors is an integer number (20066315563176).

Almost surely, 2^{40132631126351} is an apocalyptic number.

40132631126351 is a deficient number, since it is larger than the sum of its proper divisors (1).

40132631126351 is an equidigital number, since it uses as much as digits as its factorization.

40132631126351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 77760, while the sum is 38.

Adding to 40132631126351 its reverse (15362113623104), we get a palindrome (55494744749455).

The spelling of 40132631126351 in words is "forty trillion, one hundred thirty-two billion, six hundred thirty-one million, one hundred twenty-six thousand, three hundred fifty-one".