Base | Representation |
---|---|
bin | 100101011000000111… |
… | …010011001111101111 |
3 | 10211120221100101002212 |
4 | 211120013103033233 |
5 | 1124143022431021 |
6 | 30234205441035 |
7 | 2620350665132 |
oct | 453007231757 |
9 | 124527311085 |
10 | 40133014511 |
11 | 16025049897 |
12 | 794057017b |
13 | 3a277b5185 |
14 | 1d2a114219 |
15 | 109d50d85b |
hex | 9581d33ef |
40133014511 has 2 divisors, whose sum is σ = 40133014512. Its totient is φ = 40133014510.
The previous prime is 40133014463. The next prime is 40133014513. The reversal of 40133014511 is 11541033104.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40133014511 - 26 = 40133014447 is a prime.
It is a super-2 number, since 2×401330145112 (a number of 22 digits) contains 22 as substring.
Together with 40133014513, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40133014513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066507255 + 20066507256.
It is an arithmetic number, because the mean of its divisors is an integer number (20066507256).
Almost surely, 240133014511 is an apocalyptic number.
40133014511 is a deficient number, since it is larger than the sum of its proper divisors (1).
40133014511 is an equidigital number, since it uses as much as digits as its factorization.
40133014511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 40133014511 its reverse (11541033104), we get a palindrome (51674047615).
The spelling of 40133014511 in words is "forty billion, one hundred thirty-three million, fourteen thousand, five hundred eleven".
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