40133511115261 has 2 divisors, whose sum is σ = 40133511115262. Its totient is φ = 40133511115260.

The previous prime is 40133511115241. The next prime is 40133511115349. The reversal of 40133511115261 is 16251111533104.

It is a happy number.

40133511115261 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27216890754361 + 12916620360900 = 5216981^2 + 3593970^2 .

It is a cyclic number.

It is not a de Polignac number, because 40133511115261 - 2¹³ = 40133511107069 is a prime.

It is a super-2 number, since 2×40133511115261² (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40133511115241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066755557630 + 20066755557631.

It is an arithmetic number, because the mean of its divisors is an integer number (20066755557631).

Almost surely, 2^{40133511115261} is an apocalyptic number.

It is an amenable number.

40133511115261 is a deficient number, since it is larger than the sum of its proper divisors (1).

40133511115261 is an equidigital number, since it uses as much as digits as its factorization.

40133511115261 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 34.

Adding to 40133511115261 its reverse (16251111533104), we get a palindrome (56384622648365).

The spelling of 40133511115261 in words is "forty trillion, one hundred thirty-three billion, five hundred eleven million, one hundred fifteen thousand, two hundred sixty-one".