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40135110343 is a prime number
BaseRepresentation
bin100101011000001111…
…010010111011000111
310211121002021212001021
4211120033102323013
51124144042012333
630234322412011
72620404544336
oct453017227307
9124532255037
1040135110343
1116026250489
127941201007
133a2806a103
141d2a4dbd1d
15109d7c482d
hex9583d2ec7

40135110343 has 2 divisors, whose sum is σ = 40135110344. Its totient is φ = 40135110342.

The previous prime is 40135110341. The next prime is 40135110403. The reversal of 40135110343 is 34301153104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 40135110343 - 21 = 40135110341 is a prime.

It is a super-2 number, since 2×401351103432 (a number of 22 digits) contains 22 as substring.

Together with 40135110341, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40135110341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20067555171 + 20067555172.

It is an arithmetic number, because the mean of its divisors is an integer number (20067555172).

Almost surely, 240135110343 is an apocalyptic number.

40135110343 is a deficient number, since it is larger than the sum of its proper divisors (1).

40135110343 is an equidigital number, since it uses as much as digits as its factorization.

40135110343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 40135110343 its reverse (34301153104), we get a palindrome (74436263447).

The spelling of 40135110343 in words is "forty billion, one hundred thirty-five million, one hundred ten thousand, three hundred forty-three".