401355511141421 has 2 divisors, whose sum is σ = 401355511141422. Its totient is φ = 401355511141420.

The previous prime is 401355511141411. The next prime is 401355511141423. The reversal of 401355511141421 is 124141115553104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 323992404044521 + 77363107096900 = 17999789^2 + 8795630^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-401355511141421 is a prime.

It is a super-3 number, since 3×401355511141421³ (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 401355511141423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401355511141423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200677755570710 + 200677755570711.

It is an arithmetic number, because the mean of its divisors is an integer number (200677755570711).

Almost surely, 2^{401355511141421} is an apocalyptic number.

It is an amenable number.

401355511141421 is a deficient number, since it is larger than the sum of its proper divisors (1).

401355511141421 is an equidigital number, since it uses as much as digits as its factorization.

401355511141421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48000, while the sum is 38.

Adding to 401355511141421 its reverse (124141115553104), we get a palindrome (525496626694525).

The spelling of 401355511141421 in words is "four hundred one trillion, three hundred fifty-five billion, five hundred eleven million, one hundred forty-one thousand, four hundred twenty-one".