Base | Representation |
---|---|
bin | 10010010000001001110001… |
… | …10110011010001100111111 |
3 | 12021010002201000212021112021 |
4 | 21020010320312122030333 |
5 | 20230102420312341234 |
6 | 221210513323421011 |
7 | 11311555522515151 |
oct | 1110047066321477 |
9 | 167102630767467 |
10 | 40137423168319 |
11 | 11875204aa8454 |
12 | 4602a99984767 |
13 | 1951c34339089 |
14 | 9ca9397b6ad1 |
15 | 4990ee5d79b4 |
hex | 248138d9a33f |
40137423168319 has 2 divisors, whose sum is σ = 40137423168320. Its totient is φ = 40137423168318.
The previous prime is 40137423168317. The next prime is 40137423168419. The reversal of 40137423168319 is 91386132473104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40137423168319 - 21 = 40137423168317 is a prime.
It is a super-2 number, since 2×401374231683192 (a number of 28 digits) contains 22 as substring.
Together with 40137423168317, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40137423168317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20068711584159 + 20068711584160.
It is an arithmetic number, because the mean of its divisors is an integer number (20068711584160).
Almost surely, 240137423168319 is an apocalyptic number.
40137423168319 is a deficient number, since it is larger than the sum of its proper divisors (1).
40137423168319 is an equidigital number, since it uses as much as digits as its factorization.
40137423168319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2612736, while the sum is 52.
The spelling of 40137423168319 in words is "forty trillion, one hundred thirty-seven billion, four hundred twenty-three million, one hundred sixty-eight thousand, three hundred nineteen".
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