40137423168419 has 2 divisors, whose sum is σ = 40137423168420. Its totient is φ = 40137423168418.

The previous prime is 40137423168319. The next prime is 40137423168421. The reversal of 40137423168419 is 91486132473104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40137423168419 - 2¹⁶ = 40137423102883 is a prime.

It is a super-2 number, since 2×40137423168419² (a number of 28 digits) contains 22 as substring.

Together with 40137423168421, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (40137423168439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20068711584209 + 20068711584210.

It is an arithmetic number, because the mean of its divisors is an integer number (20068711584210).

Almost surely, 2^{40137423168419} is an apocalyptic number.

40137423168419 is a deficient number, since it is larger than the sum of its proper divisors (1).

40137423168419 is an equidigital number, since it uses as much as digits as its factorization.

40137423168419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3483648, while the sum is 53.

The spelling of 40137423168419 in words is "forty trillion, one hundred thirty-seven billion, four hundred twenty-three million, one hundred sixty-eight thousand, four hundred nineteen".