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4014131211479 is a prime number
BaseRepresentation
bin111010011010011100110…
…111010110110011010111
3112012202011201001121211002
4322122130313112303113
51011231420042231404
612312022202533515
7563003625216314
oct72323467266327
915182151047732
104014131211479
111308424469a44
12549b7050729b
132316b965862c
14dc3dc00dd0b
156e63b8aac1e
hex3a69cdd6cd7

4014131211479 has 2 divisors, whose sum is σ = 4014131211480. Its totient is φ = 4014131211478.

The previous prime is 4014131211439. The next prime is 4014131211487. The reversal of 4014131211479 is 9741121314104.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4014131211479 is a prime.

It is a super-2 number, since 2×40141312114792 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4014131211439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007065605739 + 2007065605740.

It is an arithmetic number, because the mean of its divisors is an integer number (2007065605740).

Almost surely, 24014131211479 is an apocalyptic number.

4014131211479 is a deficient number, since it is larger than the sum of its proper divisors (1).

4014131211479 is an equidigital number, since it uses as much as digits as its factorization.

4014131211479 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 38.

The spelling of 4014131211479 in words is "four trillion, fourteen billion, one hundred thirty-one million, two hundred eleven thousand, four hundred seventy-nine".