Base | Representation |
---|---|
bin | 111010011010011100110… |
… | …111010110110010101111 |
3 | 112012202011201001121202121 |
4 | 322122130313112302233 |
5 | 1011231420042231224 |
6 | 12312022202533411 |
7 | 563003625216226 |
oct | 72323467266257 |
9 | 15182151047677 |
10 | 4014131211439 |
11 | 1308424469a08 |
12 | 549b70507267 |
13 | 2316b96585cb |
14 | dc3dc00dcbd |
15 | 6e63b8aabe4 |
hex | 3a69cdd6caf |
4014131211439 has 2 divisors, whose sum is σ = 4014131211440. Its totient is φ = 4014131211438.
The previous prime is 4014131211437. The next prime is 4014131211479. The reversal of 4014131211439 is 9341121314104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4014131211439 - 21 = 4014131211437 is a prime.
It is a super-2 number, since 2×40141312114392 (a number of 26 digits) contains 22 as substring.
Together with 4014131211437, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4014131211437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007065605719 + 2007065605720.
It is an arithmetic number, because the mean of its divisors is an integer number (2007065605720).
Almost surely, 24014131211439 is an apocalyptic number.
4014131211439 is a deficient number, since it is larger than the sum of its proper divisors (1).
4014131211439 is an equidigital number, since it uses as much as digits as its factorization.
4014131211439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 34.
The spelling of 4014131211439 in words is "four trillion, fourteen billion, one hundred thirty-one million, two hundred eleven thousand, four hundred thirty-nine".
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