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4022243304127 is a prime number
BaseRepresentation
bin111010100010000000011…
…000100010001010111111
3112020112010001101121220221
4322202000120202022333
51011400023241213002
612315443145122211
7563411636655226
oct72420030421277
915215101347827
104022243304127
111310907538244
1254b655189367
132323b0187459
14dc96b535cbd
156e963b48c37
hex3a8806222bf

4022243304127 has 2 divisors, whose sum is σ = 4022243304128. Its totient is φ = 4022243304126.

The previous prime is 4022243304109. The next prime is 4022243304161. The reversal of 4022243304127 is 7214033422204.

It is an a-pointer prime, because the next prime (4022243304161) can be obtained adding 4022243304127 to its sum of digits (34).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4022243304127 - 27 = 4022243303999 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4022243304092 and 4022243304101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4022243301127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011121652063 + 2011121652064.

It is an arithmetic number, because the mean of its divisors is an integer number (2011121652064).

Almost surely, 24022243304127 is an apocalyptic number.

4022243304127 is a deficient number, since it is larger than the sum of its proper divisors (1).

4022243304127 is an equidigital number, since it uses as much as digits as its factorization.

4022243304127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 34.

The spelling of 4022243304127 in words is "four trillion, twenty-two billion, two hundred forty-three million, three hundred four thousand, one hundred twenty-seven".