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40344433 is a prime number
BaseRepresentation
bin1001100111100…
…1101101110001
32210220201011021
42121321231301
540312010213
64000415441
7666631153
oct231715561
983821137
1040344433
1120856408
1211617581
13848755c
145502ad3
15381dd8d
hex2679b71

40344433 has 2 divisors, whose sum is σ = 40344434. Its totient is φ = 40344432.

The previous prime is 40344427. The next prime is 40344439. The reversal of 40344433 is 33444304.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (40344427) and next prime (40344439).

It can be written as a sum of positive squares in only one way, i.e., 39652209 + 692224 = 6297^2 + 832^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40344433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40344398 and 40344407.

It is not a weakly prime, because it can be changed into another prime (40344439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20172216 + 20172217.

It is an arithmetic number, because the mean of its divisors is an integer number (20172217).

Almost surely, 240344433 is an apocalyptic number.

It is an amenable number.

40344433 is a deficient number, since it is larger than the sum of its proper divisors (1).

40344433 is an equidigital number, since it uses as much as digits as its factorization.

40344433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 25.

The square root of 40344433 is about 6351.7267730909. The cubic root of 40344433 is about 342.9740054589.

Adding to 40344433 its reverse (33444304), we get a palindrome (73788737).

The spelling of 40344433 in words is "forty million, three hundred forty-four thousand, four hundred thirty-three".