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404211310001 is a prime number
BaseRepresentation
bin1011110000111001101…
…11110001110110110001
31102122100011220002021022
411320130313301312301
523110311043410001
6505405255105225
741126506305512
oct5703467616661
91378304802238
10404211310001
11146474823994
1266409672215
132c169c76c55
14157c7600a09
15a7ab4ae11b
hex5e1cdf1db1

404211310001 has 2 divisors, whose sum is σ = 404211310002. Its totient is φ = 404211310000.

The previous prime is 404211309991. The next prime is 404211310003. The reversal of 404211310001 is 100013112404.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 386734734400 + 17476575601 = 621880^2 + 132199^2 .

It is a cyclic number.

It is not a de Polignac number, because 404211310001 - 218 = 404211047857 is a prime.

Together with 404211310003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (404211310003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202105655000 + 202105655001.

It is an arithmetic number, because the mean of its divisors is an integer number (202105655001).

Almost surely, 2404211310001 is an apocalyptic number.

It is an amenable number.

404211310001 is a deficient number, since it is larger than the sum of its proper divisors (1).

404211310001 is an equidigital number, since it uses as much as digits as its factorization.

404211310001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 404211310001 its reverse (100013112404), we get a palindrome (504224422405).

The spelling of 404211310001 in words is "four hundred four billion, two hundred eleven million, three hundred ten thousand, one".