40444411102031 has 2 divisors, whose sum is σ = 40444411102032. Its totient is φ = 40444411102030.

The previous prime is 40444411102019. The next prime is 40444411102033. The reversal of 40444411102031 is 13020111444404.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40444411102031 - 2¹⁰ = 40444411101007 is a prime.

It is a super-2 number, since 2×40444411102031² (a number of 28 digits) contains 22 as substring.

Together with 40444411102033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 40444411101985 and 40444411102003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40444411102033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20222205551015 + 20222205551016.

It is an arithmetic number, because the mean of its divisors is an integer number (20222205551016).

Almost surely, 2^{40444411102031} is an apocalyptic number.

40444411102031 is a deficient number, since it is larger than the sum of its proper divisors (1).

40444411102031 is an equidigital number, since it uses as much as digits as its factorization.

40444411102031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 40444411102031 its reverse (13020111444404), we get a palindrome (53464522546435).

The spelling of 40444411102031 in words is "forty trillion, four hundred forty-four billion, four hundred eleven million, one hundred two thousand, thirty-one".