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411101421149 is a prime number
BaseRepresentation
bin1011111101101111000…
…11011101111001011101
31110022010100211222220002
411332313203131321131
523213413430434044
6512505110104045
741462322265226
oct5766743357135
91408110758802
10411101421149
11149390042421
126781104b025
132c9c75862b3
1415c7c71424d
15aa6131d74e
hex5fb78dde5d

411101421149 has 2 divisors, whose sum is σ = 411101421150. Its totient is φ = 411101421148.

The previous prime is 411101421127. The next prime is 411101421151. The reversal of 411101421149 is 941124101114.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 375235879225 + 35865541924 = 612565^2 + 189382^2 .

It is a cyclic number.

It is not a de Polignac number, because 411101421149 - 224 = 411084643933 is a prime.

It is a super-4 number, since 4×4111014211494 (a number of 48 digits) contains 4444 as substring.

Together with 411101421151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411101423149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205550710574 + 205550710575.

It is an arithmetic number, because the mean of its divisors is an integer number (205550710575).

Almost surely, 2411101421149 is an apocalyptic number.

It is an amenable number.

411101421149 is a deficient number, since it is larger than the sum of its proper divisors (1).

411101421149 is an equidigital number, since it uses as much as digits as its factorization.

411101421149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 29.

The spelling of 411101421149 in words is "four hundred eleven billion, one hundred one million, four hundred twenty-one thousand, one hundred forty-nine".