Base | Representation |
---|---|
bin | 10010101100110010010000… |
… | …10100000110010110000010 |
3 | 12101121011002020012122010220 |
4 | 21112121020110012112002 |
5 | 20342212234402322242 |
6 | 223242455441003510 |
7 | 11442624262602552 |
oct | 1126311024062602 |
9 | 171534066178126 |
10 | 41121230120322 |
11 | 12114463413750 |
12 | 47416a0923596 |
13 | 19c393b8597c1 |
14 | a223c7399162 |
15 | 4b49ce423bec |
hex | 256648506582 |
41121230120322 has 32 divisors (see below), whose sum is σ = 90643986183744. Its totient is φ = 12332515123200.
The previous prime is 41121230120287. The next prime is 41121230120473. The reversal of 41121230120322 is 22302103212114.
It is a junction number, because it is equal to n+sod(n) for n = 41121230120292 and 41121230120301.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3211586079 + ... + 3211598882.
It is an arithmetic number, because the mean of its divisors is an integer number (2832624568242).
Almost surely, 241121230120322 is an apocalyptic number.
41121230120322 is an abundant number, since it is smaller than the sum of its proper divisors (49522756063422).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41121230120322 is a wasteful number, since it uses less digits than its factorization.
41121230120322 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6423185074.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 41121230120322 its reverse (22302103212114), we get a palindrome (63423333332436).
The spelling of 41121230120322 in words is "forty-one trillion, one hundred twenty-one billion, two hundred thirty million, one hundred twenty thousand, three hundred twenty-two".
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