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4112231301223 is a prime number
BaseRepresentation
bin111011110101110100000…
…101100000000001100111
3112120010101110200112011021
4323311310011200001213
51014333322203114343
612425044420152011
7603045632221003
oct73656405400147
915503343615137
104112231301223
111345a95400381
12564b89b38607
1323aa21666306
141030669cb703
1571e7de040ed
hex3bd74160067

4112231301223 has 2 divisors, whose sum is σ = 4112231301224. Its totient is φ = 4112231301222.

The previous prime is 4112231301193. The next prime is 4112231301253. The reversal of 4112231301223 is 3221031322114.

It is a balanced prime because it is at equal distance from previous prime (4112231301193) and next prime (4112231301253).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4112231301223 is a prime.

It is a super-2 number, since 2×41122313012232 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4112231301253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056115650611 + 2056115650612.

It is an arithmetic number, because the mean of its divisors is an integer number (2056115650612).

Almost surely, 24112231301223 is an apocalyptic number.

4112231301223 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112231301223 is an equidigital number, since it uses as much as digits as its factorization.

4112231301223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4112231301223 its reverse (3221031322114), we get a palindrome (7333262623337).

The spelling of 4112231301223 in words is "four trillion, one hundred twelve billion, two hundred thirty-one million, three hundred one thousand, two hundred twenty-three".